2x^2+4x=160

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Solution for 2x^2+4x=160 equation:


Simplifying
2x2 + 4x = 160

Reorder the terms:
4x + 2x2 = 160

Solving
4x + 2x2 = 160

Solving for variable 'x'.

Reorder the terms:
-160 + 4x + 2x2 = 160 + -160

Combine like terms: 160 + -160 = 0
-160 + 4x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-80 + 2x + x2) = 0

Factor a trinomial.
2((-10 + -1x)(8 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-10 + -1x)' equal to zero and attempt to solve: Simplifying -10 + -1x = 0 Solving -10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1x = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1x = 0 + 10 -1x = 0 + 10 Combine like terms: 0 + 10 = 10 -1x = 10 Divide each side by '-1'. x = -10 Simplifying x = -10

Subproblem 2

Set the factor '(8 + -1x)' equal to zero and attempt to solve: Simplifying 8 + -1x = 0 Solving 8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x = 0 + -8 -1x = 0 + -8 Combine like terms: 0 + -8 = -8 -1x = -8 Divide each side by '-1'. x = 8 Simplifying x = 8

Solution

x = {-10, 8}

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